If the solubility of a sparingly soluble salt | vedclass

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(D) For a sparingly soluble salt of the type $BA_2$,the dissociation reaction is:$BA_2(s) \rightleftharpoons B^{2+}(aq) + 2A^{-}(aq)$If the solubility

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$4x^3$

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(D) For a sparingly soluble salt of the type $BA_2$,the dissociation reaction is:$BA_2(s) \rightleftharpoons B^{2+}(aq) + 2A^{-}(aq)$If the solubility is $x \ mol \ L^{-1}$,then the concentration of $B^{2+}$ is $x \ mol \ L^{-1}$ and the concentration of $A^{-}$ is $2x \ mol \ L^{-1}$.The solubility product constant $(K_{sp})$ is given by:$K_{sp} = [B^{2+}][A^{-}]^2$$K_{sp} = (x)(2x)^2$$K_{sp} = (x)(4x^2)$$K_{sp} = 4x^3$

If the solubility of a sparingly soluble salt of the type $BA_2$ (giving three ions on dissociation of a molecule) is $x \ mol \ L^{-1}$,then its solubility product is given by

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