If the solubility product (K_{sp}) of Ni(OH)_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The dissociation of $NaOH$ is: $NaOH \rightarrow Na^+ + OH^-$. Since $NaOH$ is a strong electrolyte, $[OH^-] = 1.0 \ M$. Let the solubility of $Ni

Vedclass · Accepted Answer

$1.9 	imes 10^{-15} \ M$

Vedclass · Answer

(C) The dissociation of $NaOH$ is: $NaOH ightarrow Na^+ + OH^-$. Since $NaOH$ is a strong electrolyte, $[OH^-] = 1.0 \ M$. Let the solubility of $Ni(OH)_2$ be $s \ M$. The dissociation is: $Ni(OH)_2 ightleftharpoons Ni^{2+} + 2OH^-$. The concentration of $Ni^{2+}$ is $s$ and the total concentration of $OH^-$ is $(2s + 1.0) \ M$. Given $K_{sp} = [Ni^{2+}][OH^-]^2 = 1.9 	imes 10^{-15}$. Substituting the values: $s(2s + 1.0)^2 = 1.9 	imes 10^{-15}$. Since $s$ is very small, we can neglect $2s$ compared to $1.0$. Thus, $s(1.0)^2 = 1.9 	imes 10^{-15}$. $s = 1.9 	imes 10^{-15} \ M$.

If the solubility product $(K_{sp})$ of $Ni(OH)_2$ is $1.9 \times 10^{-15}$, the molar solubility of $Ni(OH)_2$ in $1.0 \ M \ NaOH$ is:

Similar Questions

If the concentration of $OH^{-}$ ions in the reaction $Fe(OH)_{3(s)} \rightleftharpoons Fe^{3+}_{(aq)} + 3OH^{-}_{(aq)}$ is decreased by $1/4$ times,then the equilibrium concentration of $Fe^{3+}$ will increase by $......$ times.

What is the $pH$ at which $Mg(OH)_2$ starts to precipitate from a solution containing $0.1 \ M \ Mg^{2+}$ ions? (Given $K_{sp}$ for $Mg(OH)_2 = 1.0 \times 10^{-11}$)

Evaporation of $1 \ L$ of a saturated solution of $CaCO_3$ leaves a residue of $7.0 \ g$. What is the solubility product $(K_{sp})$ for $CaCO_3$?

At $298 \ K$ temperature,the $K_{sp}$ of $Mg(OH)_2$ is $1.8 \times 10^{-11}$. If $0.1 \ M$ $NaOH$ solution is added to it,what is the concentration of $Mg^{2+}$ ions? Calculate its solubility in water.

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$BaCO_3 \downarrow + CO_2 + H_2O \longrightarrow Ba(HCO_3)_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module