If the speed of the wave shown in the figure | vedclass

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(C) From the figure,the amplitude $A = 0.05 \ m$.The distance covered by $2.5$ wavelengths is $0.25 \ m$.So,$2.5 \lambda = 0.25 \ m \implies \lambda =

Vedclass · Accepted Answer

$y = 0.05 \sin 2\pi (3300 \, t - 10 \, x)$

Vedclass · Answer

(C) From the figure,the amplitude $A = 0.05 \ m$.The distance covered by $2.5$ wavelengths is $0.25 \ m$.So,$2.5 \lambda = 0.25 \ m \implies \lambda = 0.1 \ m$.The wave speed $v = 330 \ m/s$.The frequency $f = \frac{v}{\lambda} = \frac{330}{0.1} = 3300 \ Hz$.The wave equation for a wave moving in the positive $x$-direction is given by $y = A \sin 2\pi (ft - \frac{x}{\lambda})$.Substituting the values: $y = 0.05 \sin 2\pi (3300 \, t - \frac{x}{0.1})$.$y = 0.05 \sin 2\pi (3300 \, t - 10 \, x)$.

If the speed of the wave shown in the figure is $330 \ m/s$ in the given medium,then the equation of the wave propagating in the positive $x$-direction will be (all quantities are in $M.K.S.$ units).

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