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(C) The standard $emf$ of a cell is given by $E^\circ_{	ext{cell}} = E^\circ_{	ext{cathode}} - E^\circ_{	ext{anode}}$.To maximize $E^\circ_{	ext{c

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$C$ is anode and $B$ is cathode

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(C) The standard $emf$ of a cell is given by $E^\circ_{	ext{cell}} = E^\circ_{	ext{cathode}} - E^\circ_{	ext{anode}}$.To maximize $E^\circ_{	ext{cell}}$, we must choose the cathode with the highest reduction potential and the anode with the lowest reduction potential.Given potentials: $E^\circ_A = +2.5 	ext{ V}$, $E^\circ_B = +3.0 	ext{ V}$, $E^\circ_C = -2.0 	ext{ V}$, $E^\circ_D = -1.5 	ext{ V}$.Highest potential (cathode) is $B$ $(+3.0 	ext{ V})$.Lowest potential (anode) is $C$ $(-2.0 	ext{ V})$.$E^\circ_{	ext{cell}} = E^\circ_B - E^\circ_C = 3.0 - (-2.0) = 5.0 	ext{ V}$.Thus, $C$ is the anode and $B$ is the cathode.

If the standard reduction potentials of four electrodes $A$, $B$, $C$, and $D$ are $+2.5 \text{ V}$, $+3.0 \text{ V}$, $-2.0 \text{ V}$, and $-1.5 \text{ V}$ respectively, in which case is the standard $emf$ of the cell maximum?

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