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(D) Let the two-digit number be represented as $10x + y$,where $x$ is the tens digit and $y$ is the units digit.According to the problem,the sum of th

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$22$

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(D) Let the two-digit number be represented as $10x + y$,where $x$ is the tens digit and $y$ is the units digit.According to the problem,the sum of the digits is equal to the product of the digits:$x + y = xy$Rearranging the equation to solve for $y$:$x = xy - y$$x = y(x - 1)$$y = \frac{x}{x - 1}$Since $x$ and $y$ must be integers between $1$ and $9$ (with $x 
eq 0$ for a two-digit number):If $x = 2$,then $y = \frac{2}{2 - 1} = 2$.The number is $10(2) + 2 = 22$.Check: Sum of digits $= 2 + 2 = 4$; Product of digits $= 2 	imes 2 = 4$. Both are equal.Thus,the number is $22$.

If the sum and the product of the digits of a two-digit number are the same,then the number is $\ldots \ldots \ldots \ldots$

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