If the sum of two numbers is 55 and the HCF a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the two numbers be $x$ and $y$.Given that the sum of the numbers is $x + y = 55$ $....(1)$We are given $HCF = 5$ and $LCM = 120$.We know the p

Vedclass · Accepted Answer

$\frac{11}{120}$

Vedclass · Answer

(C) Let the two numbers be $x$ and $y$.Given that the sum of the numbers is $x + y = 55$ $....(1)$We are given $HCF = 5$ and $LCM = 120$.We know the property that for any two numbers,the product of the numbers is equal to the product of their $HCF$ and $LCM$:$x 	imes y = HCF 	imes LCM$$x 	imes y = 5 	imes 120 = 600$ $....(2)$We need to find the sum of the reciprocals of the numbers,which is $\frac{1}{x} + \frac{1}{y}$.$\frac{1}{x} + \frac{1}{y} = \frac{x + y}{x 	imes y}$Substituting the values from equation $(1)$ and $(2)$:$\frac{1}{x} + \frac{1}{y} = \frac{55}{600}$Simplifying the fraction by dividing both numerator and denominator by $5$:$\frac{55 \div 5}{600 \div 5} = \frac{11}{120}$

If the sum of two numbers is $55$ and the $HCF$ and $LCM$ of these numbers are $5$ and $120$ respectively,then the sum of the reciprocals of the numbers is equal to

Similar Questions

The maximum number of students among whom $1001$ pens and $910$ pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils is:

The smallest number which when diminished by $7,$ is divisible by $12, 16, 18, 21$ and $28$ is

$L.C.M.$ and $H.C.F.$ of two numbers $x$ and $y$ are $315$ and $3,$ respectively. If $x+y=36,$ the value of $\frac{1}{x}+\frac{1}{y}$ is

Find the greatest number which will divide $3962, 4085$ and $4167$ leaving the same remainder in each case.

Find the greatest number which will divide $2112$ and $2792$ leaving the remainder $4$ in each case.

Vedclass Test Series

Exam Paper Generator

Online Exam Module