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(A) The magnification of an astronomical telescope is given by $m = -f_o / f_e$,where $f_o$ is the focal length of the objective lens and $f_e$ is the

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Object will appear very small

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(A) The magnification of an astronomical telescope is given by $m = -f_o / f_e$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece. Since the objective lens has a much larger focal length than the eyepiece $(f_o > f_e)$,the initial magnification is large. When the telescope is reversed,the eyepiece acts as the objective and the objective acts as the eyepiece. The new magnification becomes $m' = -f_e / f_o$. Since $f_e Therefore,the object will appear very small.

If a telescope is reversed,i.e.,viewed from the objective side,what happens to the appearance of the object?

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