If the temperature of a black body is doubled,the frequency at which the spectral intensity becomes maximum will be

  • A
    unchanged
  • B
    four times
  • C
    doubled
  • D
    halved

Explore More

Similar Questions

At a temperature of $2000 \; K$,the maximum energy of a black body is emitted at a wavelength of $14 \; \mu m$. When its temperature is reduced to $1000 \; K$,the wavelength corresponding to the maximum energy emitted is ....... $\mu m$.

$A$ particular star (assuming it as a black body) has a surface temperature of about $5 \times 10^4 \ K$. The wavelength in nanometers at which its radiation becomes maximum is $(b = 0.0029 \ mK)$.

The colour of a star is an indication of its

The graph of relative intensity versus wavelength for three perfectly black bodies at temperatures $T_1, T_2,$ and $T_3$ is shown below. The relationship between their temperatures is:

Wien's displacement law expresses the relationship between:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo