If the time period of a $2 \ m$ long simple pendulum is $2 \ s$,the acceleration due to gravity at the place where the pendulum is executing $S.H.M.$ is

  • A
    $\pi^{2} \ m/s^{2}$
  • B
    $9.8 \ m/s^{2}$
  • C
    $2 \pi^{2} \ m/s^{2}$
  • D
    $16 \ m/s^{2}$

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