If the total electricity required to deposit $1$ mole of a metal $M$ is equal to that of $10.7$ amperes of current for $10$ hours,the equivalent weight of the metal is (atomic weight $= M \ u$):

  • A
    $M$
  • B
    $\frac{M}{2}$
  • C
    $\frac{M}{3}$
  • D
    $\frac{M}{4}$

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