If the truth value of [(p lor q) land (q to r | vedclass

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(C) The implication $A 	o B$ is false only when $A$ is True and $B$ is False.Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (p \lan

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Truth value of $(\sim q) 	o p$ is False.

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(C) The implication $A 	o B$ is false only when $A$ is True and $B$ is False.Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (p \land q)$.Since $B$ is False, $(p \land q) = F$.Since $A$ is True, $(p \lor q) = T$, $(q 	o r) = T$, and $(\sim r) = T$.From $(\sim r) = T$, we get $r = F$.Since $(q 	o r) = T$ and $r = F$, $q$ must be $F$ (because $T 	o F$ is $F$).Since $(p \lor q) = T$ and $q = F$, $p$ must be $T$.Thus, $p = T, q = F, r = F$.Now check the options:$(A)$ $p 	o q = T 	o F = F$ (True statement).$(B)$ $p 	o r = T 	o F = F$ (True statement).$(C)$ $(\sim q) 	o p = (\sim F) 	o T = T 	o T = T$ (This is $NOT$ true as it is True).$(D)$ $(\sim p) \land r = (\sim T) \land F = F \land F = F$ (True statement).Therefore, option $(C)$ is the correct answer.

If the truth value of $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then which of the following is $NOT$ true?

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