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(A) conditional statement $A 	o B$ is false only when $A$ is true and $B$ is false.Here, $A = (p \lor q) \land (q 	o r) \land (\sim r)$ and $B = (p

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$(F, T)$

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(A) conditional statement $A 	o B$ is false only when $A$ is true and $B$ is false.Here, $A = (p \lor q) \land (q 	o r) \land (\sim r)$ and $B = (p \land q)$.Since $A$ is true, $(p \lor q)$ is true, $(q 	o r)$ is true, and $(\sim r)$ is true.From $(\sim r) = T$, we get $r = F$.Substituting $r = F$ into $(q 	o r) = T$, we get $(q 	o F) = T$, which implies $q = F$.Since $(p \lor q) = T$ and $q = F$, we must have $p = T$.Now, check $B = (p \land q) = (T \land F) = F$. This matches the condition that $B$ is false.Thus, the truth values are $p = T$ and $q = F$.Now, calculate $p 	o q = T 	o F = F$.Calculate $q 	o p = F 	o T = T$.Therefore, the truth values are $(F, T)$.

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then the truth values of $p \to q$ and $q \to p$ are respectively...

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