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(A) conditional statement $A 	o B$ is false only when $A$ is true and $B$ is false.Here, $A = [(p \vee q) \wedge (q 	o r) \wedge (\sim r)]$ and $B =

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$(F, T)$

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(A) conditional statement $A 	o B$ is false only when $A$ is true and $B$ is false.Here, $A = [(p \vee q) \wedge (q 	o r) \wedge (\sim r)]$ and $B = (p \wedge q)$.Since $B$ is false, $(p \wedge q) = F$.Since $A$ is true, $(p \vee q) = T$, $(q 	o r) = T$, and $(\sim r) = T$.From $(\sim r) = T$, we get $r = F$.Substitute $r = F$ into $(q 	o r) = T$, we get $(q 	o F) = T$, which implies $q = F$.Substitute $q = F$ into $(p \vee q) = T$, we get $(p \vee F) = T$, which implies $p = T$.Now, calculate the truth values of $p 	o q$ and $q 	o p$:$p 	o q = T 	o F = F$.$q 	o p = F 	o T = T$.Thus, the truth values are $(F, T)$.

If the truth value of the compound statement $[(p \vee q) \wedge (q \to r) \wedge (\sim r)] \to (p \wedge q)$ is false, then the truth values of $p \to q$ and $q \to p$ are respectively...

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