(D) The energy of the incident photon is given by $E = \frac{hc}{\lambda}$.Using $hc = 1240 \, eV \cdot nm$ and $\lambda = 350 \, nm$,we get $E = \fra

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Metal $A$ will not emit photo-electrons

(D) The energy of the incident photon is given by $E = \frac{hc}{\lambda}$.Using $hc = 1240 \, eV \cdot nm$ and $\lambda = 350 \, nm$,we get $E = \frac{1240}{350} \approx 3.54 \, eV$.Photo-electric emission occurs only if the energy of the incident photon is greater than the work function of the metal $(E > \Phi)$.For metal $A$: $\Phi_A = 4.8 \, eV$. Since $3.54 \, eV For metal $B$: $\Phi_B = 2.2 \, eV$. Since $3.54 \, eV > 2.2 \, eV$,metal $B$ will emit photo-electrons.Therefore,metal $A$ will not emit photo-electrons.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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If two metals $A$ and $B$ are exposed to radiation of wavelength $350 \, nm$. The work functions of metals $A$ and $B$ are $4.8 \, eV$ and $2.2 \, eV$ respectively. Choose the correct option.

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A
Metal $B$ will not emit photo-electrons
B
Both metals $A$ and $B$ will emit photo-electrons
C
Both metals $A$ and $B$ will not emit photo-electrons
D
Metal $A$ will not emit photo-electrons

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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If two metals $A$ and $B$ are exposed to radiation of wavelength $350 \, nm$. The work functions of metals $A$ and $B$ are $4.8 \, eV$ and $2.2 \, eV$ respectively. Choose the correct option.

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What is the stopping potential when a metal with a work function of $0.6 \ eV$ is illuminated with light of $2 \ eV$ (in $V$)?

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