If there are 999 bases in an RNA that code fo | vedclass

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(B) The genetic code is a triplet,meaning $1$ codon consists of $3$ bases.When a base at position $901$ is deleted,it causes a frameshift mutation fro

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$33$

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(B) The genetic code is a triplet,meaning $1$ codon consists of $3$ bases.When a base at position $901$ is deleted,it causes a frameshift mutation from that point onwards.The total number of bases remaining after the deletion is $998$.The number of bases from the point of deletion $(901)$ to the end of the $RNA$ is $999 - 901 + 1 = 99$ bases.Since each codon consists of $3$ bases,the number of codons affected by this frameshift is $99 / 3 = 33$ codons.Therefore,$33$ codons will be altered.

If there are $999$ bases in an $RNA$ that code for a protein with $333$ amino acids,and the base at position $901$ is deleted such that the length of the $RNA$ becomes $998$ bases,how many codons will be altered?

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