If there is no torsion in the suspension thread, then the time period of a magnet executing $SHM$ is

  • A
    $T=\frac{1}{2 \pi} \sqrt{\frac{M B}{I}}$
  • B
    $T=\frac{1}{2 \pi} \sqrt{\frac{I}{M B}}$
  • C
    $T=2 \pi \sqrt{\frac{I}{M B}}$
  • D
    $T=2 \pi \sqrt{\frac{M B}{I}}$

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