If three distinct points $A, B, C$ are given in the $2$-dimensional coordinate plane such that the ratio of the distance from $(1, 0)$ to the distance from $(-1, 0)$ is equal to $\frac{1}{2}$,then the circumcentre of the triangle $ABC$ is at the point

  • A
    $\left( \frac{5}{3}, 0 \right)$
  • B
    $(0, 0)$
  • C
    $\left( \frac{1}{3}, 0 \right)$
  • D
    $(3, 0)$

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