If three elements X,Y and Z crystallise in a | vedclass

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(C) The number of corners in a cube is $8$,and each corner atom is shared by $8$ unit cells. So,the effective number of $X$ atoms $= 8 	imes (1/8) =

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$XYZ_{3}$

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(C) The number of corners in a cube is $8$,and each corner atom is shared by $8$ unit cells. So,the effective number of $X$ atoms $= 8 	imes (1/8) = 1$.The $Y$ atom is at the body centre,which is not shared by any other unit cell. So,the effective number of $Y$ atoms $= 1$.The number of edges in a cube is $12$,and each edge centre atom is shared by $4$ unit cells. So,the effective number of $Z$ atoms $= 12 	imes (1/4) = 3$.Therefore,the ratio of atoms $X:Y:Z$ is $1:1:3$,and the formula of the compound is $XYZ_{3}$.

If three elements $X$,$Y$ and $Z$ crystallise in a $ccp$ lattice with $X$ atoms at the corners,$Y$ atoms at the cube centre and $Z$ atoms at the edges centre,the formula of the compound will be

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