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(C) When two dice are thrown,the total number of outcomes is $6 	imes 6 = 36$. The possible sums range from $2$ to $12$. The prime numbers in this ra

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$5/12$

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(C) When two dice are thrown,the total number of outcomes is $6 	imes 6 = 36$. The possible sums range from $2$ to $12$. The prime numbers in this range are $2, 3, 5, 7, 11$. Favourable outcomes for each sum: Sum $= 2$: $(1, 1)$ - $1$ case Sum $= 3$: $(1, 2), (2, 1)$ - $2$ cases Sum $= 5$: $(1, 4), (2, 3), (3, 2), (4, 1)$ - $4$ cases Sum $= 7$: $(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)$ - $6$ cases Sum $= 11$: $(5, 6), (6, 5)$ - $2$ cases Total favourable cases $= 1 + 2 + 4 + 6 + 2 = 15$. Required probability $= \frac{15}{36} = \frac{5}{12}$.

If two dice are thrown together,then the probability that the sum of the numbers appearing on them is a prime number is:

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