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Question

(A) The electromagnetic spectrum is arranged in order of increasing frequency or decreasing wavelength.The general order of wavelengths for these radi

Vedclass · Accepted Answer

$\lambda_m > \lambda_v > \lambda_x$

Vedclass · Answer

(A) The electromagnetic spectrum is arranged in order of increasing frequency or decreasing wavelength.The general order of wavelengths for these radiations is: $\lambda_{	ext{microwave}} > \lambda_{	ext{visible}} > \lambda_{	ext{X-rays}}$.Given that $\lambda_m$ represents the wavelength of microwaves, $\lambda_v$ represents the wavelength of visible rays, and $\lambda_x$ represents the wavelength of $X$-rays.Therefore, the correct relation is $\lambda_m > \lambda_v > \lambda_x$.Thus, the correct option is $A$.

List-$I$	List-$II$
$(1)$ $700\, nm$ to $1\, mm$	$(i)$ Vibration of atoms and molecules
$(2)$ $1\, nm$ to $400\, nm$	$(ii)$ Inner shell electrons in atoms moving from one energy level to a lower level
$(3)$ $< 10^{-3}\, nm$	$(iii)$ Radioactive decay of the nucleus
$(4)$ $1\, mm$ to $0.1\, m$	$(iv)$ Magnetron valve

If wavelengths of visible rays, microwaves, and $X$-rays are $\lambda_v$, $\lambda_m$, and $\lambda_x$ respectively, then which of the following relations is correct?

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