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Question

(B) Let the fraction be $x$.According to the problem,we multiply the fraction by itself $(x 	imes x = x^2)$ and divide the product by its reciprocal

Vedclass · Accepted Answer

$2 \frac{2}{3}$

Vedclass · Answer

(B) Let the fraction be $x$.According to the problem,we multiply the fraction by itself $(x 	imes x = x^2)$ and divide the product by its reciprocal $(\frac{1}{x})$.So,the equation is: $x^2 \div \frac{1}{x} = 18 \frac{26}{27}$.$x^2 	imes x = \frac{18 	imes 27 + 26}{27}$.$x^3 = \frac{486 + 26}{27} = \frac{512}{27}$.Taking the cube root on both sides: $x = \sqrt[3]{\frac{512}{27}} = \frac{8}{3}$.Converting to a mixed fraction: $x = 2 \frac{2}{3}$.

If we multiply a fraction by itself and divide the product by its reciprocal,the fraction thus obtained is $18 \frac{26}{27}$. The original fraction is

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