If we use phenolphthalein as an indicator in | vedclass

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(A) In the titration of $Na_2CO_3$ with $HCl$ using phenolphthalein,the reaction proceeds as: $Na_2CO_3 + HCl \rightarrow NaHCO_3 + NaCl$. Phenolphtha

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No visible change will occur

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(A) In the titration of $Na_2CO_3$ with $HCl$ using phenolphthalein,the reaction proceeds as: $Na_2CO_3 + HCl \rightarrow NaHCO_3 + NaCl$. Phenolphthalein changes color in the $pH$ range of $8.2$ to $10.0$. At the end point of this reaction,the solution contains $NaHCO_3$,which is weakly basic,but the phenolphthalein indicator becomes colourless as the $pH$ drops below $8.2$. Therefore,the correct observation is that the solution becomes colourless.

If we use phenolphthalein as an indicator in a titration of $Na_2CO_3$ with $HCl$,the usual result is:

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