If n_e and v_d are the number of electrons an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a semiconductor, as the temperature increases, more covalent bonds are broken, which leads to an increase in the number of free electrons $(n_e

Vedclass · Accepted Answer

$n_e$ increases and $v_d$ decreases

Vedclass · Answer

(A) In a semiconductor, as the temperature increases, more covalent bonds are broken, which leads to an increase in the number of free electrons $(n_e)$.Thus, $n_e$ increases.However, the drift velocity $(v_d)$ is related to the relaxation time $(	au)$ by the formula $v_d = \frac{eE	au}{m}$.As temperature increases, the frequency of collisions between electrons and the lattice increases, which causes the relaxation time $(	au)$ to decrease.Consequently, the drift velocity $(v_d)$ decreases.Therefore, $n_e$ increases and $v_d$ decreases.

If $n_e$ and $v_d$ are the number of electrons and drift velocity in a semiconductor, respectively, what happens when the temperature is increased?

Similar Questions

$A$ semiconductor is doped with phosphorous atoms as an impurity. The impurity levels created in the semiconductor are close to the

In $n$-type semiconductor,electrons are majority charge carriers,but it does not show any negative charge. The reason is:

Minority carriers in a $p$-type semiconductor are

In an $n$-type semiconductor, electrons are majority charge carriers and holes are minority charge carriers. The charge of an $n$-type semiconductor is

To obtain $P$-type $Si$ semiconductor,we need to dope pure $Si$ with

Vedclass Test Series

Exam Paper Generator

Online Exam Module