In $CO_2$,$C$ is $sp$ hybridised using $s$ and $p_x$ orbitals. Then:

  • A
    $CO_2$ is present in $YZ$ plane
  • B
    $CO_2$ is not present in $XY$ plane
  • C
    $p_z$ orbital of $O$ is used for $\sigma$ bonding
  • D
    $CO_2$ is present in infinite planes

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Similar Questions

What is the type of hybridization in $IF_5$?

What is $sp^{2}$ hybridization? Give its characteristics.

Difficult
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Choose the correct code of characteristics for the given order of hybrid orbitals of the same atom,$sp < sp^2 < sp^3$:
$(i)$ Electronegativity
$(ii)$ Bond angle between same hybrid orbitals
$(iii)$ Size
$(iv)$ Energy level

Difficult
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In which one of the following pairs do the two species have identical shape,but differ in hybridisation?

Match List-$I$ with List-$II$ :
List-$I$ (Species) List-$II$ (Hybrid Orbitals)
$(a)$ $SF_{4}$ $(i)$ $sp^{3}d^{2}$
$(b)$ $IF_{5}$ $(ii)$ $d^{2}sp^{3}$
$(c)$ $NO_{2}^{+}$ $(iii)$ $sp^{3}d$
$(d)$ $NH_{4}^{+}$ $(iv)$ $sp^{3}$
$(v)$ $sp$

Choose the correct answer from the options given below :

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