In $XeO_3$ and $XeF_6$ the oxidation state of $Xe$ is

Assertion $(A)$: The boiling points of noble gases increase from $He$ to $Xe$.
Reason $(R)$: The interatomic van der Waals' attractive forces increase from $He$ to $Xe$.
The correct answer is:

$Xe + 2F_2 \xrightarrow[673 \ K, 5-6 \ bar]{Ni} ?$
Which compound is formed by the above reaction?

Complete hydrolysis of $XeF_4$ and $XeF_6$ gives its oxides $P$ and $Q$, respectively. Identify $P$ and $Q$.

$XeF_2 + H_2O \to$ Products (The possible products are)

The structure of $XeOF_4$ is