In XeF_2,the hybridisation of Xe is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ single bonds with $F$ atoms,using $2$ electrons.The remaining $6$ electr

Vedclass · Accepted Answer

$sp^3d$

Vedclass · Answer

(B) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ single bonds with $F$ atoms,using $2$ electrons.The remaining $6$ electrons form $3$ lone pairs.The steric number is calculated as: $	ext{Steric Number} = 	ext{Number of bond pairs} + 	ext{Number of lone pairs} = 2 + 3 = 5$.$A$ steric number of $5$ corresponds to $sp^3d$ hybridisation.

In $XeF_2$,the hybridisation of $Xe$ is:

Similar Questions

In the series ethane,ethylene and acetylene,the $C-H$ bond energy is

In which of the following compounds does the $C$ atom use $sp^3$ hybrid orbitals for bonding?

What is the $s$-character content in an $sp^3$ hybrid orbital?

In the given reaction,the number of $sp^{2}$ hybridised carbon atoms in compound '$X$' is $.....$

Select the systematic diagram which represents the correct change in the bond angle in the hybrid orbital of beryllium.

Vedclass Test Series

Exam Paper Generator

Online Exam Module