In Delta ABC,A-P-B,A-Q-C and overline{PQ} par | vedclass

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(B) Given that in $\Delta ABC$,$\overline{PQ} \parallel \overline{BC}$.According to the Basic Proportionality Theorem (Thales Theorem),if a line is dr

Vedclass · Accepted Answer

$3$

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(B) Given that in $\Delta ABC$,$\overline{PQ} \parallel \overline{BC}$.According to the Basic Proportionality Theorem (Thales Theorem),if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points,then the other two sides are divided in the same ratio.Therefore,$\frac{AP}{AB} = \frac{AQ}{AC}$.Given values are $AP = 2$,$AB = 6$,and $AC = 9$.Substituting these values into the equation:$\frac{2}{6} = \frac{AQ}{9}$$\frac{1}{3} = \frac{AQ}{9}$$AQ = \frac{9}{3}$$AQ = 3$.Thus,the value of $AQ$ is $3$.

In $\Delta ABC$,$A-P-B$,$A-Q-C$ and $\overline{PQ} \parallel \overline{BC}$. If $AP = 2$,$AB = 6$ and $AC = 9$,find $AQ$.

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