In $\square ABCD$,$\overline{AB} \parallel \overline{CD}$ and $\overline{AC} \cap \overline{BD} = \{M\}$. If $\frac{AB}{CD} = \frac{2}{1}$ and $AC = 15$,find $MA$ and $MC$.
- A$MA = 10, MC = 5$
- B$MA = 5, MC = 10$
- C$MA = 7.5, MC = 7.5$
- D$MA = 9, MC = 6$
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