In $\Delta ABC$,$AB > BC > CA$. Write the measure of the angles of the triangle in ascending order.
(A) In a triangle,the angle opposite to the longer side is larger.
Given the side lengths are in the order $AB > BC > CA$.
The angle opposite to side $AB$ is $\angle C$.
The angle opposite to side $BC$ is $\angle A$.
The angle opposite to side $CA$ is $\angle B$.
Since $AB > BC > CA$,it follows that $\angle C > \angle A > \angle B$.
Therefore,the angles in ascending order are $\angle B < \angle A < \angle C$.
Given the side lengths are in the order $AB > BC > CA$.
The angle opposite to side $AB$ is $\angle C$.
The angle opposite to side $BC$ is $\angle A$.
The angle opposite to side $CA$ is $\angle B$.
Since $AB > BC > CA$,it follows that $\angle C > \angle A > \angle B$.
Therefore,the angles in ascending order are $\angle B < \angle A < \angle C$.
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