In Delta ABC and Delta XYZ,angle A = angle X, | vedclass

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(D) Given that in $\Delta ABC$ and $\Delta XYZ$:$1$. $\angle A = \angle X$$2$. $\angle C = \angle Z$$3$. $AB = XY$By the Angle-Angle-Side $(AAS)$ cong

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$XYZ$

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(D) Given that in $\Delta ABC$ and $\Delta XYZ$:$1$. $\angle A = \angle X$$2$. $\angle C = \angle Z$$3$. $AB = XY$By the Angle-Angle-Side $(AAS)$ congruence criterion,since two angles and the included side between them are not equal,we look at the correspondence. Here,$\angle A$ corresponds to $\angle X$,$\angle C$ corresponds to $\angle Z$,and the side $AB$ corresponds to $XY$. Since $\angle A = \angle X$ and $\angle C = \angle Z$,the third angle $\angle B$ must be equal to $\angle Y$ (by Angle Sum Property).Thus,the correspondence is $A \leftrightarrow X$,$B \leftrightarrow Y$,and $C \leftrightarrow Z$.Therefore,$\Delta ABC \cong \Delta XYZ$.

In $\Delta ABC$ and $\Delta XYZ$,$\angle A = \angle X$,$\angle C = \angle Z$ and $AB = XY$,then $\Delta ABC \cong \Delta \ldots \ldots \ldots$

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