In Delta ABC, angle B = angle C, AB = 5 text{ | vedclass

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(B) Given that in $\Delta ABC$, $\angle B = \angle C$.According to the property of triangles, sides opposite to equal angles are equal.Therefore, the

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$18$

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(B) Given that in $\Delta ABC$, $\angle B = \angle C$.According to the property of triangles, sides opposite to equal angles are equal.Therefore, the side opposite to $\angle B$ is $AC$ and the side opposite to $\angle C$ is $AB$.Thus, $AC = AB$.Given $AB = 5 	ext{ cm}$, so $AC = 5 	ext{ cm}$.We are also given $BC = 8 	ext{ cm}$.The perimeter of $\Delta ABC = AB + BC + AC$.Perimeter $= 5 	ext{ cm} + 8 	ext{ cm} + 5 	ext{ cm} = 18 	ext{ cm}$.

In $\Delta ABC$, $\angle B = \angle C$, $AB = 5 \text{ cm}$, and $BC = 8 \text{ cm}$. Then, the perimeter of $\Delta ABC$ is: (in $\text{ cm}$)

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