In Delta ABC,AB = 6 text{ cm} and BC = 9 text | vedclass

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(A) According to the triangle inequality theorem,the sum of the lengths of any two sides of a triangle must be greater than the length of the third si

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) According to the triangle inequality theorem,the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.In $\Delta ABC$,the sum of sides $AB$ and $BC$ must be greater than $AC$.Therefore,$AB + BC > AC$.Substituting the given values: $6 	ext{ cm} + 9 	ext{ cm} > AC$.$15 	ext{ cm} > AC$,which means $AC Thus,the length of side $AC$ must be less than $15 	ext{ cm}$.

In $\Delta ABC$,$AB = 6 \text{ cm}$ and $BC = 9 \text{ cm}$,then $AC < \dots \text{ cm}$.

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