In $\Delta ABC$,$\angle B$ is a right angle. Then,according to Pythagoras' theorem,$\ldots \ldots \ldots$ holds good.
- A$AB^{2} = AC^{2} + BC^{2}$
- B$AC^{2} = AB^{2} + BC^{2}$
- C$BC^{2} = AB^{2} + AC^{2}$
- D$AC^{2} = AB \cdot BC$
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