In Fe(CO)_5 and Cr(CO)_6,how many CO ligands | vedclass

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(A) The $CO$ ligand acts as a $2$-electron donor,while the $NO$ ligand acts as a $3$-electron donor.For $Fe(CO)_5$: Total valence electrons = $8 + (5

Vedclass · Accepted Answer

$3, 6$

Vedclass · Answer

(A) The $CO$ ligand acts as a $2$-electron donor,while the $NO$ ligand acts as a $3$-electron donor.For $Fe(CO)_5$: Total valence electrons = $8 + (5 	imes 2) = 18$. To replace $CO$ with $NO$ while maintaining $18$ electrons,we replace $3$ $CO$ ($6$ $e^-$) with $2$ $NO$ ($6$ $e^-$),resulting in $Fe(CO)_2(NO)_2$.For $Cr(CO)_6$: Total valence electrons = $6 + (6 	imes 2) = 18$. To replace $CO$ with $NO$ while maintaining $18$ electrons,we replace $6$ $CO$ ($12$ $e^-$) with $4$ $NO$ ($12$ $e^-$),resulting in $Cr(NO)_4$.Thus,the number of $CO$ ligands replaced are $3$ and $6$ respectively.

$LIST-I$ (Substances)	$LIST-II$ (Element Present)
$A$. Ziegler catalyst	$I$. Rhodium
$B$. Blood pigment	$II$. Cobalt
$C$. Wilkinson catalyst	$III$. Iron
$D$. Vitamin $B_{12}$	$IV$. Titanium

In $Fe(CO)_5$ and $Cr(CO)_6$,how many $CO$ ligands can be replaced by $NO$ to maintain the $18$ electron rule?

Similar Questions

Match List-$I$ with List-$II$:

$LIST-I$ (Substances) $LIST-II$ (Element Present)

$A$. Ziegler catalyst $I$. Rhodium

$B$. Blood pigment $II$. Cobalt

$C$. Wilkinson catalyst $III$. Iron

$D$. Vitamin $B_{12}$ $IV$. Titanium

Choose the correct answer from the options given below:

Finely divided iron combines with $CO$ to give

Which of the following compounds is not considered an organometallic compound?

Which of the following compounds does not contain a metal-carbon bond?

The structure of ferrocene is $Fe(\eta ^5 - C_5H_5)_2$.

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