In beta^{-} decay, a neutron transforms into | vedclass

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(B) In $\beta^{-}$ decay, a neutron inside the nucleus decays into a proton, an electron ($\beta^{-}$ particle), and an anti-neutrino $(\bar{
u}_{e})

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Anti-neutrino

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(B) In $\beta^{-}$ decay, a neutron inside the nucleus decays into a proton, an electron ($\beta^{-}$ particle), and an anti-neutrino $(\bar{
u}_{e})$.The equation is given by: $n ightarrow p + e^{-} + \bar{
u}_{e}$.Here, the particle '$x$' represents the anti-neutrino.This process is governed by the conservation of lepton number, where the electron has a lepton number of $+1$ and the anti-neutrino has a lepton number of $-1$, ensuring the total lepton number remains $0$ as it was for the neutron.

In $\beta^{-}$ decay, a neutron transforms into a proton within the nucleus according to the equation:
$\text{neutron} \rightarrow \text{proton} + \beta^{-} + x$
In this equation, the particle represented by '$x$' is:

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In $\beta^{-}$ decay, a neutron transforms into a proton within the nucleus according to the equation:$\text{neutron} \rightarrow \text{proton} + \beta^{-} + x$In this equation, the particle represented by '$x$' is: