In an L-R circuit,for the case of increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a direct current source is connected to an $L-R$ series circuit,the current does not reach its maximum value instantaneously due to the self-

Vedclass · Accepted Answer

$I = I_0 (1 - e^{-Rt/L})$

Vedclass · Answer

(B) When a direct current source is connected to an $L-R$ series circuit,the current does not reach its maximum value instantaneously due to the self-induced electromotive force in the inductor.The growth of current in an $L-R$ circuit is given by the differential equation $L(dI/dt) + IR = E$.Solving this equation with the initial condition $I(0) = 0$,we get the expression for current as a function of time:$I(t) = I_0 (1 - e^{-Rt/L})$where $I_0 = E/R$ is the maximum steady-state current and $	au = L/R$ is the time constant of the circuit.

In an $L-R$ circuit,for the case of increasing current,the magnitude of current can be calculated by using the formula:

Similar Questions

The unit of $L/R$ is (where $L$ = inductance and $R$ = resistance).

In which of the following circuits is the current maximum just after the switch $S$ is closed?

$A$ bulb of $100\, W$ is connected in parallel with an ideal inductance of $1\, H$. This arrangement is connected to a $90\, V$ battery through a switch. On pressing the switch,the

The current in an $LR$ circuit builds up to $3/4$ of its steady state value in $4 \, s$. The time constant of this circuit is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module