In an $NPN$ transistor,$10^{8}$ electrons enter the emitter in $10^{-8} \ s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor are respectively:

  • A
    $0.98$ and $49$
  • B
    $0.99$ and $99$
  • C
    $0.95$ and $50$
  • D
    $0.90$ and $90$

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