In a 1000 , m race,A can beat B by 80 , m and | vedclass

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Question

(A) In a $1000 \, m$ race,when $A$ runs $1000 \, m$,$B$ runs $1000 - 80 = 920 \, m$.So,the ratio of speeds of $A$ and $B$ is $A:B = 1000:920 = 25:23$.

Vedclass · Accepted Answer

$135.2$

Vedclass · Answer

(A) In a $1000 \, m$ race,when $A$ runs $1000 \, m$,$B$ runs $1000 - 80 = 920 \, m$.So,the ratio of speeds of $A$ and $B$ is $A:B = 1000:920 = 25:23$.When $B$ runs $1000 \, m$,$C$ runs $1000 - 60 = 940 \, m$.So,the ratio of speeds of $B$ and $C$ is $B:C = 1000:940 = 50:47$.To find the ratio $A:C$,we multiply the ratios: $\frac{A}{C} = \frac{A}{B} 	imes \frac{B}{C} = \frac{25}{23} 	imes \frac{50}{47} = \frac{1250}{1081}$.This means when $A$ runs $1250 \, m$,$C$ runs $1081 \, m$.When $A$ runs $1000 \, m$,$C$ runs $\frac{1081}{1250} 	imes 1000 = \frac{1081 	imes 4}{5} = \frac{4324}{5} = 864.8 \, m$.Therefore,$A$ beats $C$ by $1000 - 864.8 = 135.2 \, m$.

In a $1000 \, m$ race,$A$ can beat $B$ by $80 \, m$ and $B$ can beat $C$ by $60 \, m$. In the same race,$A$ can beat $C$ by (in $m$):

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