In a 1000, m race,A beats B by 100, m and C b | vedclass

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(A) In a $1000\, m$ race,when $A$ runs $1000\, m$,$B$ runs $1000 - 100 = 900\, m$.When $A$ runs $1000\, m$,$C$ runs $1000 - 200 = 800\, m$.Therefore,t

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$150$

Vedclass · Answer

(A) In a $1000\, m$ race,when $A$ runs $1000\, m$,$B$ runs $1000 - 100 = 900\, m$.When $A$ runs $1000\, m$,$C$ runs $1000 - 200 = 800\, m$.Therefore,the ratio of distances covered by $B$ and $C$ is $B : C = 900 : 800 = 9 : 8$.This means when $B$ runs $9\, m$,$C$ runs $8\, m$.In a race of $1350\, m$,when $B$ runs $1350\, m$,the distance covered by $C$ is $\frac{8}{9} 	imes 1350 = 8 	imes 150 = 1200\, m$.Thus,$B$ beats $C$ by $1350 - 1200 = 150\, m$.

In a $1000\, m$ race,$A$ beats $B$ by $100\, m$ and $C$ by $200\, m$. By how many meters can $B$ beat $C$ in a race of $1350\, m$?

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