In a 125 amino acid sequence,if the codon for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $UAA$ is one of the three stop codons (nonsense codons) which do not code for any amino acid.If the codon for the $25^{	ext{th}}$ amino acid is m

Vedclass · Accepted Answer

a polypeptide of $24$ amino acids is formed

Vedclass · Answer

(A) $UAA$ is one of the three stop codons (nonsense codons) which do not code for any amino acid.If the codon for the $25^{	ext{th}}$ amino acid is mutated to $UAA$,the translation process will be terminated at that specific position because no $tRNA$ molecule can recognize the stop codon to bring the next amino acid.Consequently,the ribosome will release the growing peptide chain after the $24^{	ext{th}}$ amino acid.Therefore,a polypeptide chain consisting of $24$ amino acids will be formed.

In a $125$ amino acid sequence,if the codon for the $25^{\text{th}}$ amino acid is mutated to $UAA$,then:

Similar Questions

The codon $AUG$ has a dual function. It is an initiation codon and also codes for:

Which of the following is the initiation codon?

The sequence of amino acids in a polypeptide is determined by which of the following?

$UUU$ codes for:

Which $RNA$ carries the genetic code?

Vedclass Test Series

Exam Paper Generator

Online Exam Module