In a $\triangle ABC$,if $a=2, b=3$ and $\sin A=\frac{2}{3}$,then $\angle B=$

  • A
    $\frac{\pi}{2}$
  • B
    $\frac{\pi}{6}$
  • C
    $\frac{\pi}{3}$
  • D
    $\frac{\pi}{4}$

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