In a $BCC$ lattice containing $X$ and $Y$ type of atoms, $X$ type of atoms are present at the corners and $Y$ type of atoms are present at the body center. In its unit cell, if three atoms are missing from the corners, the formula of the compound is:

  • A
    $X_5 Y_8$
  • B
    $X_8 Y_5$
  • C
    $X_3 Y_5$
  • D
    $X_5 Y_3$

Explore More

Similar Questions

$A$ compound crystallizes in a $NaCl$ type structure. What is the percentage of unoccupied tetrahedral voids?

Explain the calculation of the number of atoms in a body-centered cubic $(bcc)$ unit cell.

Difficult
View Solution

$A$ compound formed by elements $A$ and $B$ crystallizes in a cubic structure where $A$ atoms are at the corners of the cube and $B$ atoms are at the center of the cube. What is the formula of the compound?

The ratio of anion radius to cation radius of a crystal is $10 : 9.3$. Then, the coordination number of the cation in the crystal is

For $bcc$ cubic coordination the value of radius ratio is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo