In a DNA molecule,one chain contains 22 thymi | vedclass

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Question

(B) According to the base pairing rules of $DNA$ (Chargaff's rule),thymine $(T)$ pairs with adenine $(A)$ and guanine $(G)$ pairs with cytosine $(C)$.

Vedclass · Accepted Answer

$170\ \mathring{A}$

Vedclass · Answer

(B) According to the base pairing rules of $DNA$ (Chargaff's rule),thymine $(T)$ pairs with adenine $(A)$ and guanine $(G)$ pairs with cytosine $(C)$.In one strand,there are $22$ thymine bases. These will pair with $22$ adenine bases on the opposite strand.In the opposite strand,there are $28$ guanine bases. These will pair with $28$ cytosine bases on the first strand.Total number of base pairs = $22 + 28 = 50$ base pairs.The distance between two consecutive base pairs in a $B-DNA$ helix is $3.4\ \mathring{A}$ $(0.34\ nm)$.Total length of $DNA$ = (Total number of base pairs) $	imes$ (Distance between two base pairs).Total length = $50 	imes 3.4\ \mathring{A} = 170\ \mathring{A}$.

List-$I$	List-$II$
$a$. Bacteriophage $\phi \times 174$	$i$. $48502$ base pairs
$b$. Bacteriophage lambda	$ii$. $5386$ nucleotides
$c$. Escherichia coli	$iii$. $3.3 \times 10^9$ base pairs
$d$. Haploid content of human $DNA$	$iv$. $4.6 \times 10^6$ base pairs

In a $DNA$ molecule,one chain contains $22$ thymine and its opposite chain contains $28$ guanine. What is the length of this $DNA$ in $\mathring{A}$?

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