In a DNA molecule,if cytosine is 18%,then the | vedclass

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(B) According to Chargaff's rule,in a double-stranded $DNA$ molecule,the amount of adenine $(A)$ is equal to the amount of thymine $(T)$,and the amoun

Vedclass · Accepted Answer

$32$

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(B) According to Chargaff's rule,in a double-stranded $DNA$ molecule,the amount of adenine $(A)$ is equal to the amount of thymine $(T)$,and the amount of guanine $(G)$ is equal to the amount of cytosine $(C)$.Given that cytosine $(C)$ = $18\%$,then guanine $(G)$ must also be $18\%$.The total percentage of all four bases is $100\%$,so $A + T + G + C = 100\%$.Since $A = T$ and $G = C$,we can write: $2A + 2C = 100\%$.Substituting the value of $C$: $2A + 2(18\%) = 100\%$.$2A + 36\% = 100\%$.$2A = 100\% - 36\% = 64\%$.$A = 64\% / 2 = 32\%$.Therefore,the percentage of adenine is $32\%$.

In a $DNA$ molecule,if cytosine is $18\%$,then the percentage of adenine would be: (in $\%$)

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