In a box there are $8$ red,$7$ blue,and $6$ green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
- A$\frac{2}{3}$
- B$\frac{3}{4}$
- C$\frac{1}{3}$
- D$\frac{1}{2}$
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View SolutionLet $A$ and $B$ be two events in a random experiment. If $P(A \cap \overline{B}) = 0.1$, $P(\overline{A} \cap B) = 0.2$ and $P(B) = 0.5$, then $P(\overline{A} \cap \overline{B}) = $
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