In a capacitive circuit,the reactance of a ca | vedclass

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(B) The capacitive reactance $X_{C}$ is given by the formula: $X_{C} = \frac{1}{2 \pi f C}$.From this formula,it is clear that the capacitive reactanc

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$\frac{X_{C}}{4}$

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(B) The capacitive reactance $X_{C}$ is given by the formula: $X_{C} = \frac{1}{2 \pi f C}$.From this formula,it is clear that the capacitive reactance is inversely proportional to the frequency,i.e.,$X_{C} \propto \frac{1}{f}$.Let the initial frequency be $f$ and the initial reactance be $X_{C}$.Let the new frequency be $f' = 4f$ and the new reactance be $X_{C}'$.Using the proportionality $X_{C} \cdot f = 	ext{constant}$,we get:$X_{C}' \cdot f' = X_{C} \cdot f$$X_{C}' \cdot (4f) = X_{C} \cdot f$$X_{C}' = \frac{X_{C}}{4}$.

In a capacitive circuit,the reactance of a capacitor at frequency $f$ is $X_{C}$. What will be its reactance at frequency $4f$?

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