In a capillary tube of radius R,a straight th | vedclass

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(C) The rise of water $h$ in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{ho g R_{eff}}$,where $R_{eff}$ is the effective rad

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$\frac{2 T}{(R-r) \rho g}$

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(C) The rise of water $h$ in a capillary tube is given by the formula $h = \frac{2T \cos 	heta}{ho g R_{eff}}$,where $R_{eff}$ is the effective radius of the meniscus.In this case,the water rises in the annular space between the capillary tube of radius $R$ and the wire of radius $r$.The effective radius for the annular space is the difference between the radii,$R_{eff} = R - r$.Assuming the contact angle $	heta = 0$ for water and glass/metal,we have $\cos 	heta = 1$.Substituting these values into the formula,we get $h = \frac{2T}{ho g (R - r)}$.

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