In a certain code language,'3a, 2b, 7c' means | vedclass

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(D) Let the given statements be:$1$) $3a, 2b, 7c$ = 'Truth is Eternal'$2$) $7c, 9a, 8b, 3a$ = 'Enmity is not Eternal'$3$) $9a, 4d, 2b, 8b$ = 'Truth do

Vedclass · Accepted Answer

$9a$

Vedclass · Answer

(D) Let the given statements be:$1$) $3a, 2b, 7c$ = 'Truth is Eternal'$2$) $7c, 9a, 8b, 3a$ = 'Enmity is not Eternal'$3$) $9a, 4d, 2b, 8b$ = 'Truth does not perish'Comparing $(1)$ and $(2)$,the common codes are $3a$ and $7c$,and the common words are 'is' and 'Eternal'. Thus,$3a$ and $7c$ represent 'is' and 'Eternal' in some order.Comparing $(2)$ and $(3)$,the common code is $9a$ and $8b$,and the common word is 'not'. Wait,let's re-evaluate:From $(2)$ and $(3)$,the common codes are $9a$ and $8b$,and the common word is 'not'. This implies 'not' is either $9a$ or $8b$.Looking at $(2)$ again: $7c, 9a, 8b, 3a$ = 'Enmity is not Eternal'. Since $3a$ and $7c$ are 'is' and 'Eternal',the remaining codes $9a$ and $8b$ must represent 'Enmity' and 'not'.From $(3)$,$9a, 4d, 2b, 8b$ = 'Truth does not perish'. Since $9a$ and $8b$ are 'not' and 'Enmity' (from statement $2$),and 'not' is common to $(2)$ and $(3)$,one of $9a$ or $8b$ must be 'not'.Actually,comparing $(2)$ and $(3)$,the common codes are $9a$ and $8b$. The common word is 'not'.In $(2)$,'Enmity' is the only word left after accounting for 'is','Eternal',and 'not'.Since $9a$ and $8b$ are 'not' and 'Enmity',and 'not' is in $(3)$ while 'Enmity' is not,we look for the code unique to $(2)$. The code $8b$ is present in $(2)$ and $(3)$,so $8b$ must be 'not'. Therefore,$9a$ must be 'Enmity'.

Digit	$7$	$2$	$1$	$5$	$3$	$9$	$8$	$6$	$4$
Letter	$W$	$L$	$M$	$S$	$I$	$N$	$D$	$J$	$B$

In a certain code language,'$3a, 2b, 7c$' means 'Truth is Eternal','$7c, 9a, 8b, 3a$' means 'Enmity is not Eternal' and '$9a, 4d, 2b, 8b$' means 'Truth does not perish'. Which of the following means 'enmity' in that language?

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