In a certain code language:(A) 'pit na som' m | vedclass

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(B) To decode the language,we analyze the common words:$1$. From $(A)$ and $(B)$,'na' is common,and 'water' is common. So,'na' = 'water'.$2$. From $(A

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$(C)$ only

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(B) To decode the language,we analyze the common words:$1$. From $(A)$ and $(B)$,'na' is common,and 'water' is common. So,'na' = 'water'.$2$. From $(A)$ and $(C)$,'pit' is common,and 'me' is common. So,'pit' = 'me'.$3$. From $(B)$ and $(D)$,'jo' is common,and 'life' is common. So,'jo' = 'life'.Statement $(C)$ ('tub od pit' = 'give me toy') provides information about 'give','toy',and 'od',which are not required to decode the core relationships between the other sentences. Thus,statement $(C)$ is redundant for the primary decoding process.

Digit	$7$	$2$	$1$	$5$	$3$	$9$	$8$	$6$	$4$
Letter	$W$	$L$	$M$	$S$	$I$	$N$	$D$	$J$	$B$

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