In a circle with radius $7 \, cm$,the area of a minor sector can be $\ldots \ldots \ldots \ldots \, cm^{2}$.

  • A
    $150$
  • B
    $105$
  • C
    $88$
  • D
    $55$

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Find the area of the minor segment of a circle of radius $14 \, cm$,when the angle of the corresponding sector is $60^{\circ}$. (in $cm^{2}$)

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In $\odot(O, 5.6)$,$\overline{OA}$ and $\overline{OB}$ are radii perpendicular to each other. Then,the difference between the area of the minor sector formed by minor $\widehat{AB}$ and the corresponding minor segment is $\ldots \ldots \ldots \ldots cm^2$.

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